Write an assembly language program to count the number of 1’s in a byte stored in memory location 2000H.

Step 1: Point to memory location 2000H

Step 2: Load register A (Accumulator) with the content of memory location

Step 3: Set a counter to loop through each bits of number, Say C

Step 4: Set a counter to store the number of one’s (1’s) in the byte, Say B

Step 5: Rotate the content of accumulator to left through carry

Step 6: If no carry found from Step 5 then jump to Step 8

Step 7: Else increase the counter B by one (if carry found)

Step 8: Decrease counter C by one

Step 9: Until the value at counter C is 0 repeat from Step 5

Step 10: Terminate the program. (When C is 0)

Label	Instruction	Comments
	LXI H 2000H;	HL points at location 2000H
	MOV A, M;	Loads A with the content of M
	MVI C, 08H;	Sets up counter for number of bits
	MVI B, 00H;	Sets counter to count number of ones
jump2:	RAL;	Rotates accumulator left through carry
	JNC jump1;	On no carry jumps to jump1:
	INR B;	Increases counter B by one
jump1:	DCR C;	Decreases counter C by one
	JNZ jump2;	When C is not zero jumps to jump2:
	HLT;	Terminates the program